C, Programming blockade (beginner)

Hey folks, I have the following problem: I try in C-programming, but somehow I get the not so down as specifying asked me to ...

Write the 1x1 (10 to 10 / with bow) <



The final product should look like this:

1x1 = 1

1x2 = 2

...

10x9 = 90

10x10 = 10



I show you how it looks to m moment with me, but is not ready yet ..

include

int main ()

{

int a=1,b=2,c=3,d=4,e=5,f=6,g=7,h=8,i=9,j=10; int x=10; int y=0; int z=0; while(y[Kleiner Als Zeichen]x) { y++; z=a*y; printf("Z:%d\n",z); }

}



The while loop I wanted then just insert so often.

Coming out is doing in my way, and then as the:

Z: 1

Z: 2

Z: 3

Z: 4

Z: 5

Z: 6

Z: 7

Z: 8

Z: 9

Z: 10



My question is now, as I get the as easy as possible to the fact that instead of the Z each 1x1 ... 10x10 I have got? I get that just will not go ...

--answer--

I normally do not to let programs work without yourself because I do not like to give a solution on a silver platter but you seem to have great trouble understanding. I've done the code in my Dropbox, here is the link: https://www.dropbox.com/s/epudyeeuz314p3n/1x1.c?dl=0

If you have any problems with legibility or any row do not understand, let me know.

LG

This contribution Maybe it helps yes here: https://www.c-plusplus.net/forum/150541-full

Here for loops offer.

for (int i = 1; i <= 10; i ++)

for (int j = 1; j <= 10; j ++)

printf ( "Z:% d \ n", i * j);

The best answer

Date: 2018-12-22 Views: 1

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