Hello, how to do arithmetic with potencies when none of power laws accesses? In our math book deals only with the laws .... Can my please jmd the example vorrechen? 6²x2³ =? Thanks;) Lg

Hello, how to do arithmetic with potencies when none of power laws accesses? In our math book deals only with the laws .... Can my please jmd the example vorrechen? 6²x2³ =? Thanks;) Lg

You calculate normal just 6 ^ 2 which is 6 times 6 So 36 the second power is 2 ^ 3 2 times 2 times 2 is 8. Then you have to count only 36 times 8 and that is 288. If in your math book searched for a simplification? Often namely said: 6 ^ 3 times 4 ^ 3 and is then to be simplified. Then we can write: (6 x 4) ^ 3, ie 24 ^. 3 I do not know how it is in your math book but if only calculate is a task you need to expect as I have explained above. If there is oversimplifying it then as just grade the example. Hope I could help

You have until 6 high 2 count so you have to get 36 2 thus highly expected 3: 36x8 and then expect only together 36x8 = 288 done! I hope konnze help

Generally Always expect the power and then multiply. So here only 6² = 36 and 2³ = 8 and then 36x8

there is a potency law for this bill, but I know it by heart not, look in your math book vlt times in the next chapter otherwise just google the net, good luck;)

6² = 36 ... 2³ = 8 => 36 * 8 = 288