Can the term (§ represents the radical sign): *simplify* §2x + y§ *§2x-y§ by the first root law: So § (2x + y)* (2x-y) §. If not, then why?

Can the term (§ represents the radical sign): *simplify* §2x + y§ *§2x-y§ by the first root law: So § (2x + y)* (2x-y) §. If not, then why?

you can again write something beautiful that perhaps?

especially with staple. so is indeed impossible to detect from which each term the root is to be drawn.

Ah, I understand how you wrote that.

SOLUTION:

§2x + y§§2x-y§ = § (2x + y) (2x-y) § = $ (4x ^ 2 - y ^ 2) §

Side note: If you can not send any roots, please write in potency Form (p is the root of q is q ^ (1 / p).).

If I have understood it correctly, is your Term:

(2x + y) ^ 0.5 * (2x-y) ^ 0.5

You can also make the power rule advantage you here. The first root law, that is, the first power law is applicable. To arrive at a "Endwurzel", you multiply both latches and pull from the root. Thus you come to the term:

(4x²-Y²) ^ 0.5

If you have any questions, write to me: D

Yes, if a mark is between the roots, you can write under a root both terms;